HIWILMA BLOG's: How.To.Solve.It.By.Computer

Sabtu, 16 April 2016

How.To.Solve.It.By.Computer

Assalamu'alaikum wr.wb

4.1

Algoritma:

Judul: Array Order Reversal

Deklarasi:

m, n, c, d integer

first[10] [10], second[10] [10], sum[10] [10]

Deskripsi:

m,n ← input

for(c=0;c<m;c++) then

for(d=0;d<n;d++) then

for(c=0;c<m;c++) then

for(d=0;d<n;d++)then

write(‘first[d][c]’);

for(c=0;c<m;c++) then

for(d=0;d<n;d++)then

write(‘sum[c][d]=first[c][d]+first[d][c]’)

for(c=0;c<m;c++)then

for(d=0;d<n;d++)then

write(‘sum[c][d]’)

Source Code:
#include <iostream>
using namespace std;
/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char** argv) {
int m,n,c,d,first[10][10],second[10][10],sum[10][10];
cout<<" masukan baris dan colom : \n";
cin>>m>>n;
cout<<"masukan angka : \n";
for(c=0;c<m;c++){
for(d=0;d<n;d++){
cin>>first[c][d];
}
cout<<endl;
}
cout<<" balikannya : \n";
for(c=0;c<m;c++){
for(d=0;d<n;d++){
cout<<first[d][c];
}
cout<<endl;
}

for(c=0;c<m;c++){
for(d=0;d<n;d++){
sum[c][d]=first[c][d]+first[d][c];
}
}
cout<<"jumlah\n";
for(c=0;c<m;c++){
for(d=0;d<n;d++){
cout<<sum[c][d]<<"\t";
cout<<endl;
}
}

return 0;
}

Dev C++:

Output:

Source Code:
#include <iostream>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */
using namespace std;

int main(int argc, char** argv) {
    int x[100];

    for(int i=0;i<=100;i++){
        x[i]=i;
        cout<<"x["<<x[i]<<"]:=x["<<x[i]+1<<"]"<<endl;

    }
    return 0;
}

Dev C++: